49m^2-3=0

Solution for 49m^2-3=0 equation:

49m^2-3=0

a = 49; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·49·(-3)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{3}}{2*49}=\frac{0-14\sqrt{3}}{98}
=-\frac{14\sqrt{3}}{98}
=-\frac{\sqrt{3}}{7}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{3}}{2*49}=\frac{0+14\sqrt{3}}{98}
=\frac{14\sqrt{3}}{98}
=\frac{\sqrt{3}}{7}
$